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In an estimation of bromine by Carius method, 1 . 6 g of an organic compound gave 1 . 88 g of AgBr . The mass percentage of bromine in the compound is … . . ( Atomic mass, Ag = 108 ,   Br = 80   gmol - 1

Correct answer

50

Step-by-step solution

if molar mass of compound is M 1 . 6   /   M = 1 . 88   /   188 = 0 . 01 so m = 160 gram/mole Now % of bromine = 80 / 160 × 100 % = 50 %

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