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JEE Main
Exam
JEE Main
Subject
Chemistry
Chapter
Carboxylic Acid Derivatives

JEE Main · Chemistry · Carboxylic Acid Derivatives

An ester A(C _ 4 H _ 8 O _ 2 ), on treatment with excess methyl...

An ester A(C4H8O2),{\text{A(C}}_{4} {H}_{8} {O}_{2} \text{),} on treatment with excess methyl magnesium chloride followed by acidification, gives an alcohol B\text{B} as the sole organic product. Alcohol B,\text{B,} on oxidation with NaOCl\text{NaOCl} followed by acidification, gives acetic acid. Ester A\text{A} is:An ester A(C _ 4 H _ 8 O _ 2 ), on treatment with excess methyl magnesium chloride followed by acidification, gives anAn ester A(C _ 4 H _ 8 O _ 2 ), on treatment with excess methyl magnesium chloride followed by acidification, gives anAn ester A(C _ 4 H _ 8 O _ 2 ), on treatment with excess methyl magnesium chloride followed by acidification, gives anAn ester A(C _ 4 H _ 8 O _ 2 ), on treatment with excess methyl magnesium chloride followed by acidification, gives anAn ester A(C _ 4 H _ 8 O _ 2 ), on treatment with excess methyl magnesium chloride followed by acidification, gives an

Options

  1. AAssertion : Magnification of a convex mirror is always positive, but that of a concave mirror may be both positive or
  2. BAssertion : Magnification of a convex mirror is always positive, but that of a concave mirror may be both positive or
  3. CAssertion : Magnification of a convex mirror is always positive, but that of a concave mirror may be both positive or
  4. DAssertion : Magnification of a convex mirror is always positive, but that of a concave mirror may be both positive or

Correct answer

A. Assertion : Magnification of a convex mirror is always positive, but that of a concave mirror may be both positive or

Step-by-step solution

An ester A(C _ 4 H _ 8 O _ 2 ), on treatment with excess methyl magnesium chloride followed by acidification, gives an
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