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JEE Main
Exam
JEE Main
Subject
Chemistry
Chapter
Carboxylic Acid Derivatives

JEE Main · Chemistry · Carboxylic Acid Derivatives

An optically active compound (X) has molecular formula C _ 4 H _ 8...

An optically active compound (X)\left(X\right) has molecular formula C4H8O3{C}_{4}{H}_{8}{O}_{3}. It evolves CO2{CO}_{2} with NaHCO3{NaHCO}_{3}. \left(X\right)reactswithreacts with{LiAlH}_{4}togiveanachiralcompound.Structureof(X)to give an achiral compound. Structure of \left(X\right) is.An optically active compound (X) has molecular formula C _ 4 H _ 8 O _ 3 . It evolves CO _ 2 with NaHCO _ 3 . (X)An optically active compound (X) has molecular formula C _ 4 H _ 8 O _ 3 . It evolves CO _ 2 with NaHCO _ 3 . (X)An optically active compound (X) has molecular formula C _ 4 H _ 8 O _ 3 . It evolves CO _ 2 with NaHCO _ 3 . (X)An optically active compound (X) has molecular formula C _ 4 H _ 8 O _ 3 . It evolves CO _ 2 with NaHCO _ 3 . (X)An optically active compound (X) has molecular formula C _ 4 H _ 8 O _ 3 . It evolves CO _ 2 with NaHCO _ 3 . (X)

Options

  1. AWhich one of the following cannot function as an oxidising agent?
  2. BWhich one of the following cannot function as an oxidising agent?
  3. CWhich one of the following cannot function as an oxidising agent?
  4. DWhich one of the following cannot function as an oxidising agent?

Correct answer

C. Which one of the following cannot function as an oxidising agent?

Step-by-step solution

An optically active compound is the one which has a chiral centre. A chiral centre is the one with all different substituent attached.

Carboxylic acid on reaction with& NaHCO3{NaHCO}_{3}~gives~CO2{CO}_{2}~and on reaction with~LiAlH4{LiAlH}_{4},& it reduces to alcoholic group.

An optically active compound (X) has molecular formula C _ 4 H _ 8 O _ 3 . It evolves CO _ 2 with NaHCO _ 3 . (X)

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