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Which of the following is incorrect statement about OSF 4 ?

Options

  1. AS atom has sp 3 d hybridization
  2. BOSF 4 has distorted trigonal bipyramidal shape.
  3. CO atom is present at equatorial position.
  4. DThere is no lone pair on S.

Correct answer

B. OSF 4 has distorted trigonal bipyramidal shape.

Step-by-step solution

In OSF 4 , BP = 5, LP = 0 and hence the hybridization is sp 3 d and shape is trigonal-bipyramidal. Distortion in geometry due to presence of S=O (Bond) equatorially. S-atom does not contain any lone pair electrons.Distortion in geometry due to presence of S=O (Bond) equatorially. S-atom does not contain any lone pair electrons.

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