99 Percentile Qs Bank for JEE MainChemistryChemical Bonding and Molecular Structure
If the electronegativity of C ,   H ,   O ,   N   and S are 2 . 5 ,   2 . 1 ,   3 . 5 ,   3 . 0 and 2 . 5 , respectively, then the correct order of polarity of bonds is:
Options
- AS - O > C - N > O - H > C - H
- BS - O > C - N > C - H > O - H
- CO - H > S - O > C - N > C - H
- DC - N > C - H > O - H > S - O
Correct answer
C. O - H > S - O > C - N > C - H
Step-by-step solution
Electronegativity of atoms forming a bond is used to determine whether, the given bond will be non-polar covalent, polar covalent or ionic. It is the ability of an atom in a particular molecule to attract electrons to itself (the greater the value of EN , the greater the force of attraction by atom on electrons). If electronegativity difference is more, there is more charge separation and thus, bond is more polar. The electronegativity difference between: i Sulphur and Oxygen = 1 ii Carbon and Nitrogen = 0 . 5 iii