JEE Main2009ChemistryGeneral Organic ChemistryActual
Arrange the carbanions, ( CH ₃ )₃ C , C Cl ₃, ( CH ₃ )₂ C H , C ₆ H ₅ C H ₂ , in order of their decreasing stability :
Options
- AC ₈ H ₅ C H ₂> C Cl ₃> ( CH ₃ )₃ C > ( CH ₃ )₂ C H
- B( CH ₃ )₂ C H > C Cl ₃> C ₆ H ₅ C H ₂> ( CH ₃ )₃ C
- CC Cl ₃> C ₈ H ₅ C H ₂> ( CH ₃ )₂ C H > ( CH ₃ )₃ C
- D( CH ₃ )₃ C > ( CH ₃ )₂ C H > C ₆ H ₅ C H ₂> C Cl ₃
Correct answer
C. C Cl ₃> C ₈ H ₅ C H ₂> ( CH ₃ )₂ C H > ( CH ₃ )₃ C
Step-by-step solution
2^ carbanion is more stable than 3^ and Cl is -1 effect group.