X and Y are optically active isomers having formula C ₅ H ₉ Cl . When treated with one mole of H ₂, X gets converted to an optically inactive compound Z , but Y gives an optically active compound P . The structure of X and Y respectively ar

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X and Y are optically active isomers having formula C ₅ H ₉ Cl . When treated with one mole of H ₂, X gets converted to an optically inactive compound Z , but Y gives an optically active compound P . The structure of X and Y respectively are

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Let us consider the formula of C ₅ H ₉ Cl which is optically active. Optically active means molecule does not contain plane of symmetry. So, possible optically inactive structure of C ₅ H ₉ Cl is When, ' X^ react with 1 mole of H ₂ , it converted into optically inactive compound ' Z ' Same as (X),(Y) is optically active and give compound (P) which is inactive. When ' Y ' react with 1 mole of H ₂ , it will give ' P ' which is optically active. So, ' P ' is

X and Y are optically active isomers having formula C ₅ H ₉ Cl . When treated with one mole of H ₂, X gets converted to an optically inactive compound Z , but Y gives an optically active compound P . The structure of X and Y respectively are

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