99 Percentile Qs Bank for JEE MainChemistryGeneral Organic Chemistry
The equilibrium constant for the following reaction is
Options
- A10 11
- B10 -11
- C10 29
- D10 -29
Correct answer
A. 10 11
Step-by-step solution
Subtracting (ii) from (i) gives the desired equation, Hence equilibrium constant = 1 0 - 9 1 0 - 2 0 = 1 0 1 1 .