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99 Percentile Qs Bank for JEE MainChemistryp Block Elements (Group 15, 16, 17 & 18)

The order of first ionisation potential of NO ,   Na ,   O 2 and Xe is Na < NO < Xe = O 2 . When O 2 is made to react with a powerful oxidising agent PtF 6 , it yields O 2 + PtF 6 - . So, if PtF 6 is made to react with other mentioned species in the order of ionisation potential, the possible product(s) is(are)

Options

  1. AOnly Na + PtF 6 -
  2. BOnly NO + PtF 6 -
  3. COnly Xe PtF 6 -
  4. DNa + PtF 6 - NO + PtF 6 -  Xe + PtF 6 -

Correct answer

D. Na + PtF 6 - NO + PtF 6 -  Xe + PtF 6 -

Step-by-step solution

As PtF 6   is a powerful oxidising agent, Na + PtF 6 → Na + PtF 6 - NO + PtF 6 → NO + PtF 6 - Xe + PtF 6 → Xe + PtF 6 -

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