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99 Percentile Qs Bank for JEE MainChemistryp Block Elements (Group 15, 16, 17 & 18)

The products obtained from the following chemical reactions are respectively (i) NaOH ( hot and conc . ) + Cl 2 → (ii) XeF 6 ( excess ) + H 2 O →

Options

  1. ANaOH and XeO 3
  2. BHClO 3 and XeO 2 F 2
  3. CNaClO 3 and XeO 3
  4. DNone of these

Correct answer

C. NaClO 3 and XeO 3

Step-by-step solution

The reactions are as follows: (i) 6 NaOH ( hot and conc . ) + 3 Cl 2 → 5 NaCl + NaClO 3 + 3 H 2 O (ii) XeF 6 ( excess ) + 3 H 2 O → XeO 3 + 6HF

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