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If 92   g   Na reacts with water in open vessel at 300   K . What is the value of work done? [Assume ideal nature of the gaseous product]

Options

  1. A0 . 0
  2. B- 4988 . 4   J
  3. C- 2494 . 2   J
  4. D- 9976 . 8   J

Correct answer

B. - 4988 . 4   J

Step-by-step solution

Reaction of sodium with water will be 2 Na ( s )   +   2   H 2 O ( l )   →   2 NaOH ( aq )   +   H 2 ( g ) According to the given reaction 46 g of Na gives one mole of hydrogen gas. So, 92 g of Na will give = 92 46   =   2   moles   of   H 2   gas This is the only gaseous product so, due to this volume will increase at constant pressure. Work done at constant pressure and temperature w = - P ∆ V   =   - ∆ n g RT since produ

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