Calculate the final temperature of the gas, if one mole of an ideal gas is allowed to expand reversibly and adibatically from a temperature of 27 ° C and the work done during the process is 3 kJ . Given C V = 20 J/K

Step-by-step solution

Given number of moles =1 Initial temperature = 27 o C = 300 K Work done by the system = 3 kJ = 3000 K It will be ( - ) because work is done by the system. Heat capacity at constant volume Cv = 20 J/k We know that work done W = - n C V ( T 2 - T 1 ) ; 3000 = - 1 × 20 ( T 2 - 300 ) 3000 = - 20 T 2 + 6000 20 T 2 = 3000 T 2 = 3000 20 = 150 K