The jaws of a vernier calipers touch the inner wall of calorimeter without any undue pressure. The position of zero of vernier scale on the main scale reads 3.48. The 6 th  of vernier scale division is coinciding with any main scale division. Vernier constant of calipers is 0 . 01   cm . Find actual internal diameter of calorimeter, when it is observed that the vernier scale has a zero error of - 0 . 03 &#1

Step-by-step solution

The jaws of a vernier calipers touch the inner wall means we are measuring inner radius. Given, The main scale reading MSR = 3 . 48   cm The Least count of vernier calipers LC = 0 . 01   cm The vernier scale reading VSR = 6 Diameter of the calorimeter measured is, D = MSR + VSR × LC D = 3 . 48 + 0 . 01 × 6 = 3 . 54   cm There is a negative zero error of - 0 . 03   cm . So, the actual diameter of the calorimeter will be, D ' = D - zero   error = 3 . 54 - - 0 . 03 = 3 . 57 &#160