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Experimental Physics

JEE Main · Physics · Experimental Physics

The jaws of a vernier calipers touch the inner wall of calorimeter...

The jaws of a vernier calipers touch the inner wall of calorimeter without any undue pressure. The position of zero of vernier scale on the main scale reads 3.48. The 6th{6}^{th }of vernier scale division is coinciding with any main scale division. Vernier constant of calipers is 0.01cm.0 . 01cm . Find actual internal diameter of calorimeter, when it is observed that the vernier scale has a zero error of~−0.03cm- 0 . 03cm.
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Options

  1. A3.37cm3 . 37cm
  2. B3.57cm3 . 57cm
  3. C3.42cm3 . 42cm
  4. D3.54cm3 . 54cm

Correct answer

B. 3.57cm3 . 57cm

Step-by-step solution

The jaws of a vernier calipers& touch the inner wall means we are measuring inner radius.

Given,

The main scale reading& MSR=3.48cmMSR = 3 . 48cm

The Least count of vernier calipers~LC=0.01cmLC = 0 . 01cm

The vernier scale reading~VSR=6VSR = 6

Diameter of the calorimeter measured is,~

D=MSR+(VSR\timesLC)D = MSR + \left(VSR \timesLC\right)

D=3.48+(0.01×6)=3.54cmD = 3 . 48 + \left(0 . 01 \times6\right) = 3 . 54cm

There is a negative zero error of~−0.03cm- 0 . 03cm. So, the actual diameter of the calorimeter will be,~

D′=D−zeroerror=3.54−(−0.03)=3.57cm</p></blockquote>D^{'} = D - zeroerror = 3 . 54 - \left(-0 . 03\right) = 3 . 57cm</p></blockquote>

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