99 Percentile Qs Bank for JEE MainPhysicsExperimental Physics
The distance moved by the screw of a screw gauge is 2 m m in four rotations and there are 50 divisions on its cap. When nothing is put between its jaws, 30 th division of circular scale coincides with the reference line, with zero of circular scale lying above the reference line. When a plate is placed between the jaws, the main scale reads 2 divisions and the circular scale reads 20 divisions. The thickness of the p
Options
- A1.5 mm
- B1.2 mm
- C1.4 mm
- D1.6 mm
Correct answer
A. 1.5 mm
Step-by-step solution
Pitch = 1 2 mm least count = 0.5 mm 50 = 0.01 mm Reading = [ 2 × 1 2 + 20 × 0.01 − ( − 30 × 0.01 ) ] = 1.5 mm