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JEE Main
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Physics
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Experimental Physics

JEE Main · Physics · Experimental Physics

The distance moved by the screw of a screw gauge is 2 mm in four...

The distance moved by the screw of a screw gauge is 22 mm in four rotations and there are 5050 divisions on its cap. When nothing is put between its jaws, 30th{30}^{th} division of circular scale coincides with the reference line, with zero of circular scale lying above the reference line. When a plate is placed between the jaws, the main scale reads 22 divisions and the circular scale reads 2020 divisions. The thickness of the plate is

Options

  1. A1.5mm1.5\text{mm}
  2. B1.2mm1.2\text{mm}
  3. C1.4mm1.4\text{mm}
  4. D1.6mm1.6\text{mm}

Correct answer

A. 1.5mm1.5\text{mm}

Step-by-step solution

Pitch =12mm= \dfrac{1}{2} \text{mm}
least count =0.5mm50=0.01mm= \dfrac{0.5\text{mm}}{50} = 0.01\text{mm}
Reading =[2×12+20×0.01−(−30×0.01)]=1.5mm= [ 2 \times \dfrac{1}{2} + 20 \times 0.01 - ( - 30 \times 0.01 ) ] = 1.5\text{mm}
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