There are two vernier calipers both of which have 1 cm divided into...

There are two vernier calipers both of which have

1

cm divided into

10

equal divisions on the main scale. The Vernier scale of one of the calipers \left({C}_{1}\right)

has~

equal divisions that correspond to

main scale divisions. The Vernier scale of the other caliper \left({C}_{2}\right)

has~

10

~equal divisions that correspond to~

11

~main scale divisions. The readings of the two calipers are shown in the figure. The measured values (in

cm

) by calipers

{C}_{1}

~and~

{C}_{2}

respectively, are
There are two vernier calipers both of which have 1 cm divided into 10 equal divisions on the main scale. The Vernier

Options

C. $2 . 87$ ~and~ $2 . 83$

For caliper ${C}_{1}$

$10VSD = 9MSD$

$LC = 1MSD - 1VSD$

$LC = 0 . 01cm$

Measured value=Main scale reading $+$ vernier scale reading $\times$ least count

$= \left(2 .8 + 7 \times 0 .01\right)cm$

$= 2 . 87cm$

For caliper ${C}_{2}$

$10VSD = 11MSD$

$LC = - 0 . 01cm$ (Negative least count means we have to take $VSR$ from the right of the scale

Measured value $= \left\{2 .8 + \left(10 - 7\right) \times 0 .01\right\}cm$

$= 2 . 83cm$