99 Percentile Qs Bank for JEE MainPhysicsExperimental Physics
The main scale of a vernier caliper reads 10   mm in 10 divisions. 10 divisions of vernier scale coincide with 9 divisions of the main scale. When the two jaws of the calipers touch each other, the fifth division of the vernier coincides with a main scale division and the zero of the vernier is to the right of zero of the main scale. When a cylinder is tightly placed between the two jaws, the zero of vernier sca
Options
- A3 . 09  cm
- B3.14  cm
- C3.19  cm
- Dnone of these
Correct answer
A. 3 . 09  cm
Step-by-step solution
L C = 1 10   mm = 0 . 01   cm and e = V S D × L C = 0 . 05   cm Therefore, T S R = M S R + ( V S D × L C ) - e ⇒ T S R = 3 . 1 + ( 4 × 0 . 01 ) - 0 . 05 ⇒ T S R = 3 . 14 - 0 . 05 = 3 . 09   cm