A bullet travelling at a speed of 350 m/s enters a concrete wall and penetrates a distance of 5.0 cm before coming to rest. Determine the deceleration in m/s^2 .

Correct answer: C. 1225000 Using the third equation of motion, v^2 = u^2 + 2as Given u = 350 m/s , v = 0 m/s , and s = 5.0 cm = 0.05 m Substituting the values: 0 = (350)^2 + 2a(0.05) 0 = 122500 + 0.1a a = -1225000 m/s^2 The deceleration is the magnitude of negative acceleration, which is 1225000 m/s^2 .

Concepts Of Physics MCQ Edition [Volume 1]

Exam: Concepts Of Physics MCQ Edition [Volume 1]
Subject: Physics
Chapter: Rest and Motion Kinematics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Rest and Motion Kinematics

A bullet travelling at a speed of 350 m/s enters a concrete wall...

A bullet travelling at a speed of

350 \text{ m/s}

enters a concrete wall and penetrates a distance of

5.0 \text{ cm}

before coming to rest. Determine the deceleration in

\text{m/s}^2

Options

A $12250$
B $2450000$
C $1225000$
D $24500$

Correct answer

C. $1225000$

Step-by-step solution

Using the third equation of motion,

v^2 = u^2 + 2as

Given

u = 350 \text{ m/s}

v = 0 \text{ m/s}

, and

s = 5.0 \text{ cm} = 0.05 \text{ m}

Substituting the values:

0 = (350)^2 + 2a(0.05)

0 = 122500 + 0.1a

a = -1225000 \text{ m/s}^2

The deceleration is the magnitude of negative acceleration, which is

1225000 \text{ m/s}^2

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