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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Geometrical Optics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Geometrical Optics

Determine the maximum angle of refraction when a light ray is...

Determine the maximum angle of refraction when a light ray is refracted from glass (μ=1.50\mu = 1.50) into air.

Options

  1. Asin⁡−1(23)\sin^{-1} \left(\dfrac{2}{3}\right)
  2. B45^{}^{{}^{\circ}}
  3. C60^{}^{{}^{\circ}}
  4. D90^{}^{{}^{\circ}}

Correct answer

D. 90^{}^{{}^{\circ}}

Step-by-step solution

According to Snell's law:

μ1sin⁡i=μ2sin⁡r\mu_1 \sin i = \mu_2 \sin r

For light traveling from glass (μ1=1.50\mu_1 = 1.50) to air (μ2=1\mu_2 = 1), we have:

1.50sin⁡i=1sin⁡r1.50 \sin i = 1 \sin r

The maximum possible value for sin⁡r\sin r during refraction is 11, which occurs when the incident angle is equal to the critical angle.

When sin⁡r=1\sin r = 1, the angle of refraction is r = 90^{}^{{}^{\circ}}.

Therefore, the maximum angle of refraction is 90^{}^{{}^{\circ}}.
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