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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Geometrical Optics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Geometrical Optics

An extended object is placed at a distance of 5.0 cm from a convex...

An extended object is placed at a distance of 5.0 cm5.0 \text{ cm} from a convex lens of focal length 8.0 cm8.0 \text{ cm}. If a ray diagram is drawn to scale to locate the image, what is the distance of the image from the lens measured from this diagram?

Options

  1. A13.3 cm13.3 \text{ cm}
  2. B3.1 cm3.1 \text{ cm}
  3. C26.7 cm26.7 \text{ cm}
  4. D10.0 cm10.0 \text{ cm}

Correct answer

A. 13.3 cm13.3 \text{ cm}

Step-by-step solution

Given object distance, u=−5.0 cmu = -5.0 \text{ cm}

Focal length of the convex lens, f=+8.0 cmf = +8.0 \text{ cm}

Using the lens formula:

1v−1u=1f\dfrac{1}{v} - \dfrac{1}{u} = \dfrac{1}{f}

1v=1f+1u\dfrac{1}{v} = \dfrac{1}{f} + \dfrac{1}{u}

1v=18.0+1−5.0\dfrac{1}{v} = \dfrac{1}{8.0} + \dfrac{1}{-5.0}

1v=5−840=−340\dfrac{1}{v} = \dfrac{5 - 8}{40} = -\dfrac{3}{40}

v=−403≈−13.3 cmv = -\dfrac{40}{3} \approx -13.3 \text{ cm}

The negative sign indicates that a virtual image is formed on the same side as the object. The distance of the image from the lens is 13.3 cm13.3 \text{ cm}.
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