Concepts Of Physics MCQ Edition [Volume 1]PhysicsGeometrical Optics
An extended object is placed at a distance of 5.0 cm from a convex lens of focal length 8.0 cm . Find the position of the image from the lens formula, applying the standard Cartesian sign convention (with the object placed at u = -5.0 cm ).
Options
- A+ 40 3 cm
- B- 40 3 cm
- C+ 40 13 cm
- D- 40 13 cm
Correct answer
B. - 40 3 cm
Step-by-step solution
Given the object distance u = -5.0 cm and the focal length of the convex lens f = +8.0 cm . Using the lens formula: 1 v - 1 u = 1 f 1 v - 1 -5.0 = 1 8.0 1 v + 1 5.0 = 1 8.0 1 v = 1 8.0 - 1 5.0 1 v = 5 - 8 40 = - 3 40 v = - 40 3 cm