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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Geometrical Optics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Geometrical Optics

Two concave mirrors of equal radii of curvature R are fixed on a...

Two concave mirrors of equal radii of curvature RR are fixed on a stand facing opposite directions. The whole system has a mass mm and is kept on a frictionless horizontal table as shown in the figure. Two blocks AA and BB, each of mass mm, are placed on the two sides of the stand. At t=0t = 0, the separation between AA and the mirrors is 2R2R and also the separation between BB and the mirrors is 2R2R. The block BB moves towards the mirror at a speed vv. All collisions which take place are elastic. Taking the original position of the mirrors–stand system to be x=0x = 0 and X-axis along ABAB, find the position of the images of AA and BB at t=t = (a) Rv\dfrac{R}{v} (b) 3Rv\dfrac{3R}{v} (c) 5Rv\dfrac{5R}{v}.
Two concave mirrors of equal radii of curvature R are fixed on a stand facing opposite directions. The whole system has

Options

  1. A(a) x=−2R3,Rx = -\dfrac{2R}{3}, R
    (b) x=−2R,0x = -2R, 0
    (c) x=−3R,4R3x = -3R, \dfrac{4R}{3}
  2. B(a) x=−R3,2Rx = -\dfrac{R}{3}, 2R
    (b) x=−R,0x = -R, 0
    (c) x=−2R,5R3x = -2R, \dfrac{5R}{3}
  3. C(a) x=−3R2,Rx = -\dfrac{3R}{2}, R
    (b) x=−2R,0x = -2R, 0
    (c) x=−3R,5R3x = -3R, \dfrac{5R}{3}
  4. D(a) x=−2R3,Rx = -\dfrac{2R}{3}, R
    (b) x=−R,0x = -R, 0
    (c) x=−2R,4R3x = -2R, \dfrac{4R}{3}

Correct answer

A. (a) x=−2R3,Rx = -\dfrac{2R}{3}, R
(b) x=−2R,0x = -2R, 0
(c) x=−3R,4R3x = -3R, \dfrac{4R}{3}

Step-by-step solution

(a) x=−2R3,Rx = -\dfrac{2R}{3}, R
(b) x=−2R,0x = -2R, 0
(c) x=−3R,4R3x = -3R, \dfrac{4R}{3}
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