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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Wave Motion and Waves on a String

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Wave Motion and Waves on a String

A wave travelling on a string has the equation y = (0.10 mm) [(31.4...

A wave travelling on a string has the equation y=(0.10 mm)sin⁡[(31.4 m−1)x+(314 s−1)t]y = (0.10 \text{ mm}) \sin[(31.4 \text{ m}^{-1})x + (314 \text{ s}^{-1})t]. In which direction does the wave travel?

Options

  1. ANegative xx-direction
  2. BPositive xx-direction
  3. CPositive yy-direction
  4. DNegative yy-direction

Correct answer

A. Negative xx-direction

Step-by-step solution

The given equation of the wave is y=(0.10 mm)sin⁡[(31.4 m−1)x+(314 s−1)t]y = (0.10 \text{ mm}) \sin[(31.4 \text{ m}^{-1})x + (314 \text{ s}^{-1})t].

Comparing this with the standard wave equation y=Asin⁡(kx+ωt)y = A \sin(kx + \omega t), we observe that the argument of the sine function has a positive sign between the spatial and temporal terms.

For a point of constant phase, kx+ωt=constantkx + \omega t = \text{constant}.

Differentiating with respect to time tt, we get kdxdt+ω=0k \dfrac{dx}{dt} + \omega = 0, which gives the wave velocity v=dxdt=−ωkv = \dfrac{dx}{dt} = -\dfrac{\omega}{k}.

Since the velocity is negative, the wave travels in the negative xx-direction.
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