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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Wave Motion and Waves on a String

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Wave Motion and Waves on a String

A wave is described by the equation y = (1.0 mm) π ( x 2.0 cm - t...

A wave is described by the equation y=(1.0 mm)sin⁡πy = (1.0 \text{ mm}) \sin \pi\left(\dfrac{x}{2.0 \text{ cm}} - \dfrac{t}{0.01 \text{ s}}\right). Find the speed of the particle at x=1.0 cmx = 1.0 \text{ cm} at time t=0.01 st = 0.01 \text{ s}.

Options

  1. A5π cm s−15\pi \text{ cm s}^{-1}
  2. Bzero
  3. C10π cm s−110\pi \text{ cm s}^{-1}
  4. D20π cm s−120\pi \text{ cm s}^{-1}

Correct answer

B. zero

Step-by-step solution

The given wave equation is:

y=(1.0 mm)sin⁡π(x2.0 cm−t0.01 s)<br><br>Theparticlevelocityisgivenbythepartialderivativeofdisplacementwithrespecttotime:<br><br>y = (1.0 \text{ mm}) \sin \pi \left(\dfrac{x}{2.0 \text{ cm}} - \dfrac{t}{0.01 \text{ s}}\right)<br><br>The particle velocity is given by the partial derivative of displacement with respect to time:<br><br>v_p = ∂y∂t=(\dfrac{\partial y}{\partial t} = (1.0  mm)cos⁡π(x2.0−t0.01)×(−π0.01)<br><br>Substituting\text{ mm}) \cos \pi \left(\dfrac{x}{2.0} - \dfrac{t}{0.01}\right) \times \left(-\dfrac{\pi}{0.01}\right)<br><br>Substitutingx = 1.0  cmand\text{ cm} andt = 0.01  s:<br><br>\text{ s}:<br><br>v_p = −100πcos⁡π(1.02.0−0.010.01)<br><br>-100\pi \cos \pi \left(\dfrac{1.0}{2.0} - \dfrac{0.01}{0.01}\right)<br><br>v_p = −100πcos⁡-100\pi \cos\left(\dfrac{\pi}{2} - \pi\right)

vp=v_p =-100\pi \cos \left(-\dfrac{\pi}{2}\right)

Since cos⁡(−π2)=0\cos \left(-\dfrac{\pi}{2}\right) =0, we get:

vp=0v_p = 0

Thus, the speed of the particle is zero.
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