A string of length 40 cm and weighing 10 g is connected to a spring at one end and to a fixed wall at its other end. The spring possesses a spring constant of 160 N m^ -1 and is stretched by 1.0 cm . If a wave pulse is

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Correct answer: A. 0.05 s

The tension in the string is provided by the restoring force of the stretched spring.

T = kx = 160 \times 0.01 = 1.6 \text{ N}

The linear mass density of the string is:

\mu = \dfrac{m}{L} = \dfrac{10 \times 10^{-3}}{40 \times 10^{-2}} = 0.025 \text{ kg m}^{-1}

The speed of the transverse wave on the string is given by:

v = \sqrt{\dfrac{T}{\mu}} = \sqrt{\dfrac{1.6}{0.025}} = \sqrt{64} = 8 \text{ m s}^{-1}

The time taken by the wave pulse to travel the length of the string is:

t = \dfrac{L}{v} = \dfrac{0.4}{8} = 0.05 \text{ s}

A string of length 40 cm and weighing 10 g is connected to a spring...

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