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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Wave Motion and Waves on a String

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Wave Motion and Waves on a String

A string, 2 m long and fixed at both ends, is set into vibrations...

A string, 2 m2 \text{ m} long and fixed at both ends, is set into vibrations in its first overtone. The wave speed on the string is 200 m s−1200 \text{ m s}^{-1} and the amplitude is 0.5 cm0.5 \text{ cm}. Determine the wavelength and the frequency.

Options

  1. A2 m2 \text{ m}, 100 Hz100 \text{ Hz}
  2. B4 m4 \text{ m}, 50 Hz50 \text{ Hz}
  3. C1 m1 \text{ m}, 200 Hz200 \text{ Hz}
  4. D43 m\dfrac{4}{3} \text{ m}, 150 Hz150 \text{ Hz}

Correct answer

A. 2 m2 \text{ m}, 100 Hz100 \text{ Hz}

Step-by-step solution

For a string of length LL fixed at both ends, the wavelength of the nn-th harmonic is given by λ=2Ln\lambda = \dfrac{2L}{n}.

The first overtone corresponds to the second harmonic, so n=2n = 2.

Substituting L=2 mL = 2 \text{ m} and n=2n = 2:

λ=2×22=2 m\lambda = \dfrac{2 \times 2}{2} = 2 \text{ m}

The frequency of the wave is given by f=vλf = \dfrac{v}{\lambda}.

Given the wave speed v=200 m s−1v = 200 \text{ m s}^{-1}:

f=2002=100 Hzf = \dfrac{200}{2} = 100 \text{ Hz}
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