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Concepts Of Physics MCQ Edition [Volume 1]PhysicsWave Motion and Waves on a String

A string fixed at both ends is vibrating in its third harmonic. The equation for its vibration is given by y = (0.4 cm ) [(0.314 cm ⁻¹) x] [(600 s ⁻¹)t] . Determine the frequency of vibration.

Options

  1. A150 Hz
  2. B300 Hz
  3. C1200 Hz
  4. D600 Hz

Correct answer

B. 300 Hz

Step-by-step solution

The standard equation of a standing wave is given by y = A (kx) ( t) . Comparing the given equation y = (0.4 cm ) [(0.314 cm ⁻¹) x] [(600 s ⁻¹)t] with the standard equation, we get the angular frequency = 600 rad/s . The frequency of vibration is given by f = 2 . Substituting the value of , we get f = 600 2 = 300 Hz .

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