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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Friction

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Friction

The contact force applied by a body A on another body B is equal to...

The contact force applied by a body AA on another body BB is equal to the normal force between the two bodies. From this, it can be concluded that

Options

  1. Athe bodies may be rough but they do not slip on each other
  2. Bthe magnitude of the normal force equals the magnitude of friction
  3. Cthe surfaces are necessarily frictionless
  4. Dthe frictional force between the bodies is zero

Correct answer

D. the frictional force between the bodies is zero

Step-by-step solution

The contact force FcF_{c} between two bodies is the resultant of the normal force NN and the frictional force ff.

Fc=N2+f2F_{c} = \sqrt{N^2 + f^2}

Given that the contact force is equal to the normal force, we have Fc=NF_{c} = N.

N2+f2=N\sqrt{N^2 + f^2} = N

N2+f2=N2N^2 + f^2 = N^2

f=0f = 0

Thus, the frictional force between the bodies is zero.

The frictional force can be zero if the surfaces are frictionless, or if the surfaces are rough but there is no tendency of relative motion between them. If the surfaces are rough and the frictional force is zero, the bodies do not slip on each other.

Therefore, the frictional force is zero, and the bodies may be rough but they do not slip on each other.
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