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Concepts Of Physics MCQ Edition [Volume 2]PhysicsBohr's Model and Physics of the Atom

A hydrogen atom in the ground state absorbs an ultraviolet radiation photon of wavelength 50 nm . Assuming the entire photon energy is taken up by the electron, determine the kinetic energy of the ejected electron.

Options

  1. A11.24 eV
  2. B24.84 eV
  3. C13.60 eV
  4. D38.44 eV

Correct answer

A. 11.24 eV

Step-by-step solution

The energy of the incident photon is given by E = hc Using hc 1242 eV nm and = 50 nm : E = 1242 50 = 24.84 eV The binding energy of an electron in the ground state of a hydrogen atom is 13.6 eV . Using the photoelectric equation, the kinetic energy of the ejected electron is: K = E - W K = 24.84 eV - 13.6 eV = 11.24 eV

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