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Concepts Of Physics MCQ Edition [Volume 2]PhysicsBohr's Model and Physics of the Atom

Radiation emitted from a hydrogen discharge tube is incident on a cesium plate. Determine the maximum possible kinetic energy of the emitted photoelectrons. The work function of cesium is 1.9 eV .

Options

  1. A15.5 eV
  2. B8.3 eV
  3. C11.7 eV
  4. D1.5 eV

Correct answer

C. 11.7 eV

Step-by-step solution

The maximum energy of a photon emitted from a hydrogen discharge tube corresponds to the transition of an electron from n = to n = 1 . The energy of this incident photon is: E = 13.6 ( 1 1^2 - 1 ^2 ) = 13.6 eV According to Einstein's photoelectric equation, the maximum kinetic energy of the emitted photoelectrons is: K_ max = E - Substituting the given work function of cesium = 1.9 eV : K_ max = 13.6 - 1.9 = 11.7 eV

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