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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Electric Field and Potential

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Electric Field and Potential

Consider an attractive nuclear force acting between two protons...

Consider an attractive nuclear force acting between two protons that can be expressed as F=Ce−kr/r2F = Ce^{-kr}/r^2. Determine the dimensional formulae and appropriate SI units of CC and kk.

Options

  1. A[ML3T−2][M L^3 T^{-2}], [L][L], N m2\text{N m}^2, m\text{m}
  2. B[ML3T−2][M L^3 T^{-2}], [L−1][L^{-1}], N m2\text{N m}^2, \textm−1\textm^{-1}
  3. C[MLT−2][M L T^{-2}], [L−1][L^{-1}], N\text{N}, \textm−1\textm^{-1}
  4. D[ML2T−2][M L^2 T^{-2}], [L−2][L^{-2}], J\text{J}, \textm−2\textm^{-2}

Correct answer

B. [ML3T−2][M L^3 T^{-2}], [L−1][L^{-1}], N m2\text{N m}^2, \textm−1\textm^{-1}

Step-by-step solution

The given equation is F=Ce−krr2F = \dfrac{C e^{-kr}}{r^2}.

Since the exponent of an exponential function must be dimensionless, the term krkr is dimensionless.

[k][r]=[M0L0T0][k][r] = [M^0 L^0 T^0]

[k]=1[r]=[L−1][k] = \dfrac{1}{[r]} = [L^{-1}]

The SI unit of kk is \textm−1\textm^{-1}.

The exponential term e−kre^{-kr} is dimensionless, so the dimensions of FF and Cr2\dfrac{C}{r^2} must be the same.

[F]=[C][r2][F] = \dfrac{[C]}{[r^2]}

[C]=[F][r2]=[MLT−2][L2]=[ML3T−2][C] = [F][r^2] = [M L T^{-2}][L^2] = [M L^3 T^{-2}]

The SI unit of CC is N m2\text{N m}^2.
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