A hydrogen atom consists of one proton and one electron. It may be assumed that the electron revolves in a circle of radius 0.53 angstrom ( 1 angstrom = 10^ -10 m and is abbreviated as Å) with the proton positioned at

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Correct answer: D. 8.2 × 10^ -8 N

The magnitude of the electric force between the proton and the electron is given by Coulomb's law:

F = \dfrac{1}{4 \pi \epsilon_0} \dfrac{e^2}{r^2}

Substituting the values

e = 1.6 \times 10^{-19} \text{ C}

,

r = 0.53 \times 10^{-10} \text{ m}

, and

\dfrac{1}{4 \pi \epsilon_0} = 9 \times 10^9 \text{ N m}^2 \text{ C}^{-2}

:

F = \dfrac{9 \times 10^9 \times (1.6 \times 10^{-19})^2}{(0.53 \times 10^{-10})^2}

F = \dfrac{9 \times 10^9 \times 2.56 \times 10^{-38}}{0.2809 \times 10^{-20}}

F = \dfrac{23.04 \times 10^{-29}}{0.2809 \times 10^{-20}}

F \approx 82.02 \times 10^{-9} \text{ N}

F \approx 8.2 \times 10^{-8} \text{ N}

A hydrogen atom consists of one proton and one electron. It may be...

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