Placed on a smooth horizontal table, two charged particles, each with a charge of 2.0 × 10^ -8 C , are connected by an insulating string of length 1 m . Determine the tension in the string.

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Quantrex Academy · Accepted Answer

Correct answer: D. 3.6 × 10^ -6 N

The tension in the string balances the electrostatic force of repulsion between the two charged particles.

Using Coulomb's law, the electrostatic force is given by:

F = \dfrac{1}{4\pi\epsilon_0} \dfrac{q_1 q_2}{r^2}

Substituting the given values

q_1 = q_2 = 2.0 \times 10^{-8} \text{ C}

and

r = 1 \text{ m}

:

F = 9 \times 10^9 \times \dfrac{(2.0 \times 10^{-8}) \times (2.0 \times 10^{-8})}{1^2}

F = 9 \times 10^9 \times 4.0 \times 10^{-16}

F = 36 \times 10^{-7} \text{ N}

F = 3.6 \times 10^{-6} \text{ N}

Therefore, the tension in the string is

3.6 \times 10^{-6} \text{ N}

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Placed on a smooth horizontal table, two charged particles, each...

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