When a positive charge is moved from a region of lower potential to...

The electric potential energy $U$ of a charge $q$ at a point with electric potential $V$ is given by $U = qV$.

When the charge is moved from a region of lower potential $V_1$ to a region of higher potential $V_2$, the change in potential is $\Delta V = V_2 - V_1 > 0$.

The change in electric potential energy is $\Delta U = q \Delta V$.

Since the charge is positive ($q > 0$) and the change in potential is positive ($\Delta V > 0$), the change in potential energy $\Delta U$ is positive.

Therefore, the electric potential energy of the positive charge increases.