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Concepts Of Physics MCQ Edition [Volume 2]PhysicsPhotoelectric Effect and Wave–Particle Duality

When the frequency of incident light in a photoelectric experiment is doubled, the stopping potential will

Options

  1. Abecome more than double
  2. Bdouble exactly
  3. Chalve exactly
  4. Dbecome less than double

Correct answer

A. become more than double

Step-by-step solution

Einstein's photoelectric equation is given by eV_ s = h - , where V_ s is the stopping potential, is the frequency of incident light, and is the work function of the material. For the initial frequency , the stopping potential V_ s1 is: V_ s1 = h e - e When the frequency is doubled to 2 , the new stopping potential V_ s2 is: V_ s2 = h(2 ) e - e Rewriting the above equation: V_ s2 = 2h e - 2 e + e V_ s2 = 2 ( h e - e ) + e V_ s2 = 2V_ s1 + e Since the work function is a positive quantity, e > 0 . Therefore, V_ s2 >

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