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JEE Main 20178 AprilOnline
Exam
JEE Main
Year
2017
Date
8 April
Mode
Online
Subject
Chemistry
Chapter
Hydrogen

JEE Main 2017 · 8 April · Online · Chemistry · Hydrogen

In which of the following reactions, hydrogen peroxide acts as an...

In which of the following reactions, hydrogen peroxide acts as an oxidizing agent?

Options

  1. AHOCl+H2O2→H3O++Cl−+O2\text{H}\text{O}\text{C}\text{l} + {\text{H}}_{2}{\text{O}}_{2} \to {\text{H}}_{3}{\text{O}}^{+} + \text{C}{\text{l}}^{-} + {\text{O}}_{2}
  2. BI2+H2O2+2OH−→2I−+2H2O+O2{\text{I}}_{2} + {\text{H}}_{2}{\text{O}}_{2} + 2\text{O}{\text{H}}^{-} \to 2{\text{I}}^{-} + 2{\text{H}}_{2}\text{O} + {\text{O}}_{2}
  3. CPbS+4H2O2→PbSO4+4H2O\text{P}\text{b}\text{S} + 4{\text{H}}_{2}{\text{O}}_{2} \to \text{P}\text{b}\text{S}{\text{O}}_{4} + 4{\text{H}}_{2}\text{O}
  4. D2MnO4−+3H2O2→2MnO2+3O2+2H2O+2OH−2\text{M}\text{n}{\text{O}}_{4}^{-} + 3{\text{H}}_{2}{\text{O}}_{2} \to 2\text{M}\text{n}{\text{O}}_{2} + 3{\text{O}}_{2} + 2{\text{H}}_{2}\text{O} + 2\text{O}{\text{H}}^{-}

Correct answer

C. PbS+4H2O2→PbSO4+4H2O\text{P}\text{b}\text{S} + 4{\text{H}}_{2}{\text{O}}_{2} \to \text{P}\text{b}\text{S}{\text{O}}_{4} + 4{\text{H}}_{2}\text{O}

Step-by-step solution

The reaction in which H2O2{H}_{2}{O}_{2} is getting reduced, it will behave as oxidising agent.

2e−+2H++H2O2⟶2H2O(reduction)2{\text{e}}^{-} + 2{\text{H}}^{+} + {\text{H}}_{2}{\text{O}}_{2} ⟶ 2{\text{H}}_{2}\text{O} ( \text{r}\text{e}\text{d}\text{u}\text{c}\text{t}\text{i}\text{o}\text{n} )

S−2+4H2O⟶SO4−2+8H++8e−(oxidation){\text{S}}^{- 2} + 4{\text{H}}_{2}\text{O} ⟶ \text{S}{\text{O}}_{4}^{- 2} + 8{\text{H}}^{+} + 8{\text{e}}^{-} ( \text{o}\text{x}\text{i}\text{d}\text{a}\text{t}\text{i}\text{o}\text{n} )

\left(\text{E}\text{q}\text{u}\text{a}\text{t}\text{i}\text{o}\text{n} . 1 \times 4\right) + \left(\text{E}\text{q}\text{u}\text{a}\text{t}\text{i}\text{o}\text{n} . 2\right)<br/><br/><br /><br />\text{F}\text{i}\text{n}\text{a}\text{l}\text{r}\text{e}\text{a}\text{c}\text{t}\text{i}\text{o}\text{n}\text{P}\text{b}\text{S} + 4{\text{H}}_{2}{\text{O}}_{2} ⟶ \text{P}\text{b}\text{S}{\text{O}}_{4} + 4{\text{H}}_{2}\text{O}$

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