JEE Main20265 April 2026Evening ShiftChemistryp Block Elements (Group 13 & 14)Actual
Given below are two statements : Statement I: Aluminium upon reaction with NaOH forms [Al(OH)₆]³⁻ ion. Statement II: The geometry of ICl₄^- , ClO₃^- and IBr₂^- is square planar, pyramidal and linear respectively. In the light of the above statements, choose the correct answer from the options given below :
Options
- ABoth Statement I and Statement II are true
- BBoth Statement I and Statement II are false
- CStatement I is true but Statement II is false
- DStatement I is false but Statement II is true
Correct answer
D. Statement I is false but Statement II is true
Step-by-step solution
Statement I: Aluminium reacts with aqueous sodium hydroxide to form sodium tetrahydroxoaluminate(III) and liberates hydrogen gas. The reaction is given by: 2Al + 2NaOH + 6H₂O 2Na^+[Al(OH)₄]^- + 3H₂ The complex ion formed is [Al(OH)₄]^- , not [Al(OH)₆]³⁻ . Thus, Statement I is false. Statement II: For ICl₄^- , the central iodine atom has 7 valence electrons + 1 (from negative charge) = 8 electrons. It forms 4 sigma bonds with Cl atoms and has 2 lone pairs. The hybridization is sp^3d^2 and the shape is square planar.