The group 14 elements A and B have the first ionisation enthalpy values of 708 and 715 ~kJ ~mol^ -1 respectively. The above values are lowest among their group members. The nature of their ions A^ 2+ B^ 4+ respectively

Correct answer: C. reducing and oxidising As per given information of ionisation energy A=Sn \& B=Pb aligned & A^ +2 =Sn^ 2+ = Reducing agent & B^ +4 =Pb^ +4 = Oxidising agent aligned

JEE Main 20257 AprilMorning Shift

Exam: JEE Main
Year: 2025
Date: 7 April
Shift: Morning Shift
Subject: Chemistry
Chapter: p Block Elements (Group 13 & 14)

JEE Main 2025 · 7 April · Morning Shift · Chemistry · p Block Elements (Group 13 & 14)

The group 14 elements A and B have the first ionisation enthalpy...

The group 14 elements A and B have the first ionisation enthalpy values of

708

and

715 \mathrm{~kJ} \mathrm{~mol}^{-1}

respectively. The above values are lowest among their group members. The nature of their ions

\mathrm{A}^{2+}

\mathrm{B}^{4+}

respectively is

Options

Aboth reducing
Bboth oxidising
Creducing and oxidising
Doxidising and reducing

Correct answer

C. reducing and oxidising

Step-by-step solution

As per given information of ionisation energy

\mathrm{A}=\mathrm{Sn} \& \mathrm{ B}=\mathrm{Pb}

\begin{aligned} & \mathrm{A}^{+2}=\mathrm{Sn}^{2+}=\text{ Reducing agent } \\ & \mathrm{B}^{+4}=\mathrm{Pb}^{+4}=\text{ Oxidising agent }\end{aligned}

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