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JEE Main 202621 JanuaryMorning Shift
Exam
JEE Main
Year
2026
Date
21 January
Shift
Morning Shift
Subject
Chemistry
Chapter
p Block Elements (Group 13 & 14)

JEE Main 2026 · 21 January · Morning Shift · Chemistry · p Block Elements (Group 13 & 14)

Consider the following reactions. PbCl_ 2 +K_ 2 CrO_ 4 arrow ~A+2...

Consider the following reactions.
PbCl2+K2CrO4→ A+2KCl\mathrm{PbCl}_{2}+\mathrm{K}_{2} \mathrm{CrO}_{4} \rightarrow \mathrm{~A}+2 \mathrm{KCl}
(Hot solution)
A+NaOH⇌B+Na2CrO4\mathrm{A}+\mathrm{NaOH} \rightleftharpoons \mathrm{B}+\mathrm{Na}_{2} \mathrm{CrO}_{4}
PbSO4+4CH3COONH4→(NH4)2SO4+X\mathrm{PbSO}_{4}+4 \mathrm{CH}_{3} \mathrm{COONH}_{4} \rightarrow\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}+\mathrm{X}
In the above reactions, A,B\mathrm{A}, \mathrm{B} and X are respectively.

Options

  1. A(\mathrm{Na}_2\left[\mathrm{~Pb}(\mathrm{OH})_2\right], \mathrm{PbCrO} \mathrm{O}_4) and (\left(\mathrm{NH}_4\right)_2\left[\mathrm{~Pb}\left(\mathrm{CH}_3 \mathrm{COO}\right)_4\right])
  2. B\mathrm{Na}_{2}\left[\mathrm{~Pb}(\mathrm{OH})_{2}\right], \mathrm{PbCrO}_{4}and[Pb(NH3)4]SO4and \left[\mathrm{Pb}\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{SO}_{4}
  3. CPbCrO4,Na2[ Pb(OH)4]\mathrm{PbCrO}_{4}, \mathrm{Na}_{2}\left[\mathrm{~Pb}(\mathrm{OH})_{4}\right] and \left(\mathrm{NH}_{4}\right)_{2}[ Pb(CH3COO)4]\left[\mathrm{~Pb}\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{4}\right]
  4. DPbCrO4,Na2\mathrm{PbCrO}_{4}, \mathrm{Na}_{2}\left[\mathrm{~Pb}(\mathrm{OH})_{4}\right]and[Pb(NH3)4]SO4and \left[\mathrm{Pb}\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{SO}_{4}

Correct answer

C. PbCrO4,Na2[ Pb(OH)4]\mathrm{PbCrO}_{4}, \mathrm{Na}_{2}\left[\mathrm{~Pb}(\mathrm{OH})_{4}\right] and \left(\mathrm{NH}_{4}\right)_{2}[ Pb(CH3COO)4]\left[\mathrm{~Pb}\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{4}\right]

Step-by-step solution

Reaction 1: PbCl2+K2CrO4→PbCrO4+2KClPbCl_2 + K_2CrO_4 \rightarrow PbCrO_4 + 2KCl
A = PbCrO4PbCrO_4 (lead chromate)
Reaction 2: PbCrO4+4NaOH→Na2[Pb(OH)4]+Na2CrO4PbCrO_4 + 4NaOH \rightarrow Na_2[Pb(OH)_4] + Na_2CrO_4
B = Na2[Pb(OH)4]Na_2[Pb(OH)_4] (sodium tetrahydroxoplumbate)
Reaction 3: PbSO4+4CH3COONH4→(NH4)2SO4+(NH4)2[Pb(CH3COO)4]PbSO_4 + 4CH_3COONH_4 \rightarrow (NH_4)_2SO_4 + (NH_4)_2[Pb(CH_3COO)_4]
X = (NH4)2[Pb(CH3COO)4](NH_4)_2[Pb(CH_3COO)_4] (ammonium tetraacetatoplumbate)
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