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What is the hybridization and geometry of the compound XeOF 4   ?

Options

  1. Asp 3 d 2 and octahedral
  2. Bsp 3 d and square pyramidal
  3. Csp 3 d and trigonal bipyramidal
  4. Dsp 3 d 2 and square pyramidal

Correct answer

A. sp 3 d 2 and octahedral

Step-by-step solution

The structure of XeOF 4 is. So in this sigma bond = 5 Pi bonds = 1 , lone pairs = 1 So total hybrid orbital requires = 5 + 1 = 6 , (pi bond do not need hybrid orbitals), Hence, the hybridisation will be sp 3 d 2 . As it has one lone pair and five bond pairs, so according to VSEPR, the geometry will be square pyramidal,

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