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Decreasing order of stability of given carbocations is? (1) (2) CH 2 = CH - C ⊕ H 2 (3) C 6 H 5 - C ⊕ H 2 (4) CH 3 - C ⊕ H - CH 3

Options

  1. A3 > 2 > 4 > 1
  2. B1 > 3 > 4 > 2
  3. C1 > 3 >2 > 4
  4. D3 > 2 > 1 > 4

Correct answer

C. 1 > 3 >2 > 4

Step-by-step solution

The factors affecting carbanion stability: 1. If carbanion is on more percentage s character carbon, it will be more stable. 2. If carbanion is attached to any electron withdrawing group (groups those show negative inductive, mesomeric and hyperconjugation effect), its stability increases. 3. If carbanion is busy in aromatic stability, it will still be more stable than any other factor. Preference of effects: Aromaticity > resonance > mesomeric > hyperconjugation > inductive (1) Aromatic (2) CH 2 = CH - C ⊕ H

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