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Highly selective Backlog Qs for JEE MainChemistryThermodynamics (C)

In an isobaric process, when temperature changes from T₁ to T₂, S is equal to

Options

  1. A2.303 C_P (T₂ / T₁ )
  2. B2.303 C_P (T₂ / T₁ )
  3. CC_P (T₁ / T₂ )
  4. DC_V (T₂ / T₁ )

Correct answer

A. 2.303 C_P (T₂ / T₁ )

Step-by-step solution

The entropy change for a process, when T and P are the variables is given by S=C_P T₂ T₁ -R P₂ P₁ For an isobaric process P₁=P₂ . Hence the above equation reduces to C_P T₂ T₁ = S or S=2.303 C_P T₂ T₁ .

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