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A double ordinate PQ of the hyperbola x ² a ² - y ² ~b ² =1 is such that OPQ is equilateral, O being the centre of the hyperbola. Then the eccentricity e satisfies the relation

Options

  1. A1 < e < 2 3
  2. Be = 2 3
  3. Ce = 3 2
  4. De > 2 3

Correct answer

D. e > 2 3

Step-by-step solution

Hint: P (a , b ) POM = 30^ = 1 3 = b a = a b 3 b² a² > 1 3 1+ b² a² > 4 3 e> 2 3

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