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The distance between the foci of the hyperbola x^2-3 y^2-4 x-6 y-11=0 is

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Correct answer

C. 8

Step-by-step solution

Given, equation of hyperbola is gathered x^2-3 y^2-4 x-6 y-11=0 (x^2-4 x+4 )-3 (y^2+2 y+1 )-11 =4-3 (x-2)^2-3(y+1)^2=12 (x-2)^2 12 - (y+1)^2 4 =1 Now, e= 1+ 4 12 = 2 3 gathered Now, e= 1+ 4 12 = 2 3 Distance between foci =2 a e=2 12 2 3 =8

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