From the given list, the number of compounds with + 4 oxidation state of Sulphur SO 3 , H 2 SO 3 , SOCl 2 , SF 4 , BaSO 4 , H 2 S 2 O 7

Step-by-step solution

The total number of electrons that an atom either gains or loses in order to form a chemical bond with another atom is known as the Oxidation Number. In H 2 SO 3 Let the oxidation number of S be x. 2 ( + 1 ) + x + 3 ( - 2 ) = 0 x = + 4 Similarly the + 4 oxidation state of sulphur is shown by SOCl 2 and SF 4 . Compounds SO 3 H 2 SO 3 SOCl 2 SF 4 BaSO 4 H 2 S 2 O 7 O.S.of Sulphur: + 6 + 4 + 4 + 4 + 6 + 6