JEE Main202325 Jan 2023Morning ShiftChemistryp Block Elements (Group 15, 16, 17 & 18)Actual
Compound A reacts with NH 4 Cl and forms a compound B. Compound B reacts with H 2 O and excess of CO 2 to form compound C which on passing through or reaction with saturated NaCl solution forms sodium hydrogen carbonate. Compound A. B and C, are respectively.
Options
- ACaCl 2 , NH 3 , NH 4 HCO 3
- BCaCl 2 , NH 4 + , NH 4 2 CO 3
- CCa ( OH ) 2 , NH 3 , NH 4 HCO 3
- DCa ( OH ) 2 , NH 4 + , NH 4 2 CO 3
Correct answer
C. Ca ( OH ) 2 , NH 3 , NH 4 HCO 3
Step-by-step solution
When calcium hydroxide is reacted with crystals of ammonium chloride, the products formed as calcium chloride, ammonia and water. Ca ( OH ) 2   +   NH 4 Cl   →   CaCl 2   +   2 NH 3   +   2 H 2 O When ammonia is reacted with water and excess carbon dioxide, it forms ammonium hydrogen carbonate which on passing through with saturated NaCl solution forms hydrogen carbonate. NH 3   +   H 2 O   +   CO 2   →   NH 4 HCO 3 NH 4 HCO 3