The number of non-ionisable protons present in the product $B$ obtained from the following reaction is___ ${C}_{2}{H}_{5}OH + {PCl}_{3} \to {C}_{2}{H}_{5}Cl + A$
$A + {PCl}_{3} \to B$

Question

The number of non-ionisable protons present in the product B obtained from the following reaction is___ C _ 2 H _ 5 OH + PCl _ 3 → C _ 2 H _ 5 Cl + A A + PCl _ 3 → B

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Correct answer: 0

C _ 2 H _ 5 OH + PCl _ 3 ⟶ C _ 2 H _ 5 Cl + H _ 3 PO _ 3 H _ 3 PO _ 3 + PCl _ 3 ⟶ H _ 4 P _ 2 O _ 5 + HCl A is H _ 3 PO _ 3 ( Phosphorous acid ) The basicity of A is two B is H _ 4 P _ 2 O _ 5 (Pyrophosphorous acid) Structure of H _ 4 P _ 2 O _ 5 is as given below Hydrogen which are directly attached to the phosphorous in the above structure are non-ionisable. The Number of non-ionisable hydrogen atoms are two in the above structure.

The number of non-ionisable protons present in the product B...

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