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Most Important Selected Qs for JEE AdvancedChemistryStates of Matter

According to Maxwell's distribution of molecular speeds, for the below graph drawn for two different samples of gases A and B at temperature T₁ and T₂ respectively, which of the following statements is/are INCORRECT:

Options

  1. AIf T₁=T₂ , then molecular mass of gas B (M_B ) is greater than molecular mass of gas A (M_A ) .
  2. BIf molecular mass of gas A (M_A ) is equal to molecular mass of gas B (M_B ) , then T₁ T₂ .
  3. CIf T₁ T₂ , then molecular mass of gas B (M_B ) is necessarily less than molecular mass of gas A (M_A ) .
  4. DIf gas A is O₂ and gas B is N₂ , then considering them to be ideal gases, T₁ is necessarily less than T₂ .

Correct answer

D. If gas A is O₂ and gas B is N₂ , then considering them to be ideal gases, T₁ is necessarily less than T₂ .

Step-by-step solution

At constant temperature, decrease in molecular mass causes flattening of the graph. For same molecular mass of gas, increase in temperature causes flattening of the graph. aligned & ( V _ mp )_ T ₁ ( V _ mp )_ T ₂ & ~T ₁ M _ A T ₂ M _ B ~T ₂ ~T ₁ M _ B M _ A aligned But, M_B M_A can be less than or greater than 1 Similarly, M_A M_B T₁ T₂ If gas A is O₂ and gas B is N₂ , then M_A M_B .

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