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JEE Advanced
Exam
JEE Advanced
Subject
Chemistry
Chapter
States of Matter

JEE Advanced · Chemistry · States of Matter

According to Maxwell's distribution of molecular speeds, for the...

According to Maxwell's distribution of molecular speeds, for the below graph drawn for two different samples of gases AA and BB at temperature T1T_1 and T2T_2 respectively, which of the following statements is/are INCORRECT: According to Maxwell's distribution of molecular speeds, for the below graph drawn for two different samples of gases A

Options

  1. AIf T1=T2T_1=T_2, then molecular mass of gas B(MB)B\left(M_B\right) is greater than molecular mass of gas A(MA)A\left(M_A\right).
  2. BIf molecular mass of gas A(MA)A\left(M_A\right) is equal to molecular mass of gas B(MB)B\left(M_B\right), then T1>T2T_1 \gt T_2.
  3. CIf T1<T2T_1 \lt T_2, then molecular mass of gas B(MB)B\left(M_B\right) is necessarily less than molecular mass of gas A(MA)A\left(M_A\right).
  4. DIf gas AA is O2O_2 and gas BB is N2N_2, then considering them to be ideal gases, T1T_1 is necessarily less than T2T_2.

Correct answer

D. If gas AA is O2O_2 and gas BB is N2N_2, then considering them to be ideal gases, T1T_1 is necessarily less than T2T_2.

Step-by-step solution

At constant temperature, decrease in molecular mass causes flattening of the graph. For same molecular mass of gas, increase in temperature causes flattening of the graph. (Vmp)T1<(Vmp)T2∴ T1MA<T2MB∴ T2 T1>MBMA\begin{aligned} & \left(\mathrm{V}_{\mathrm{mp}}\right)_{\mathrm{T}_1} \lt \left(\mathrm{V}_{\mathrm{mp}}\right)_{\mathrm{T}_2} \\ & \therefore \frac{\mathrm{~T}_1}{\mathrm{M}_{\mathrm{A}}} \lt \frac{\mathrm{T}_2}{\mathrm{M}_{\mathrm{B}}} \quad \therefore \frac{\mathrm{~T}_2}{\mathrm{~T}_1} \gt \frac{\mathrm{M}_{\mathrm{B}}}{\mathrm{M}_{\mathrm{A}}} \end{aligned} But, MBMA\frac{M_B}{M_A} can be less than or greater than 1 Similarly,MAMB>T1T2\frac{M_A}{M_B} \gt \frac{T_1}{T_2} If gas AA is O2O_2 and gas BB is N2N_2, then MA>MBM_A \gt M_B.
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