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Most Important Selected Qs for JEE AdvancedChemistryThermodynamics (C)

One mole of an ideal monoatomic gas is carried through a cyclic process as shown in the P vs V plot. Identify the correct expressions

Options

  1. AW = 0 along the path A B
  2. BQ=225 R along the path A B
  3. CW =-100 R and E =-150 R along the path A C
  4. DW = 0 along the path B C

Correct answer

C. W =-100 R and E =-150 R along the path A C

Step-by-step solution

Work done along A B , W _ AB = 0 ( V is constant ) Heat gained along A B, Q_ A B =n C v T aligned & = 3 R 2 (400-250) & =225 R aligned Work done along A C , W _ AC = nR T =R(150-250)=-100 R E along A C , E _ AC = nCv T = 3 R 2 (150-250)=-150 R Work done along B C , W _ BC 0

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