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JEE Main 202118 MarchEvening Shift
Exam
JEE Main
Year
2021
Date
18 March
Shift
Evening Shift
Subject
Chemistry
Chapter
p Block Elements (Group 15, 16, 17 & 18)

JEE Main 2021 · 18 March · Evening Shift · Chemistry · p Block Elements (Group 15, 16, 17 & 18)

A xenon compound A upon partial hydrolysis gives XeO _ 2 F _ 2 ....

A xenon compound AA upon partial hydrolysis gives XeO2F2{XeO}_{2}{F}_{2}. The number of lone pair of electrons present in compound AA is ___ (Round off to the Nearest integer)A xenon compound A upon partial hydrolysis gives XeO _ 2 F _ 2 . The number of lone pair of electrons present in

Correct answer

0

Step-by-step solution

XeF6(A)+2H2O(Limitedwater)⟶XeO2F2+4HF\mathop{{XeF}_{6}}_{( A )} + \mathop{2{H}_{2}O}_{( Limitedwater )} ⟶ {XeO}_{2}{F}_{2} + 4HF

Structure of ′A′' A '

A xenon compound A upon partial hydrolysis gives XeO _ 2 F _ 2 . The number of lone pair of electrons present in

Total l.p. on (A)=19( A ) = 19

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