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JEE Main2018Chemistryp Block Elements (Group 15, 16, 17 & 18)Actual

Xenon hexafluoride on partial hydrolysis produces compounds 'X' and 'Y' and the respective oxidation states of Xe are:

Options

  1. AXeOF 2   ( + 4 )   and   XeO 3   ( + 6 )
  2. BXeOF 4   + 6   and   XeO 3   ( + 6 )
  3. CXeO 2 F 2   ( + 6 )   and   XeO 2   ( + 4 )
  4. DXeOF 4   ( + 6 )   and   XeO 2 F 2   ( + 6 )

Correct answer

D. XeOF 4   ( + 6 )   and   XeO 2 F 2   ( + 6 )

Step-by-step solution

Xenon hexafluoride on partial hydrolysis produces compounds XeOF 4 ​ and XeO 2 F 2 ​ . In the compounds, XeOF 4   and XeO 2 F 2 ​, the oxidation states of Xe are +6 and +6 respectively. XeF 6   ​ +   H 2 O     →   XeOF 4   ​ +   2 HF XeOF 4   ​ +   H 2 O     →   XeO 2 F 2   ​ +   2 HF

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